17th Jul 2026, 08:00 PM
3 Pair Polarized Replacement Lenses for Oakley Gascan OO9014 Pack
Price may vary by location, shipping cost, and availability.
$37.50
Highest: $39.98
Average: $35.92
Lowest: $18.75
Price History Graph
Offer Price Prices
Lowest: -
Average: -
Highest: -
Price History Information
You can check the price history of 3 Pair Polarized Replacement Lenses for Oakley Gascan OO9014 Pack here. This product's current Price in USA is $37.50. The average and highest prices are $35.92 and $39.98 respectively.
| Lowest Ever Price | $18.75 |
|---|---|
| 5th Mar 2025 | |
| Average Price | $35.92 |
| Based on 1792 days price tracking | |
| Highest Price | $39.98 |
| 17th Dec 2021 | |
Price History of All Variants of 3 Pair Polarized Replacement Lenses for Oakley...
Current Price in USA
| Price | $37.50 |
|---|
Recent Price Drops on 3 Pair Polarized Replacement Lenses for Oakley Gascan OO9014 Pack
Price Drop 25th Jun 2026
$37.50 → $30.00
20% drop
Price Drop 21st Nov 2025
$37.50 → $30.00
20% drop
Price Drop 4th Mar 2025
$37.50 → $18.75
50% drop
Price Drop 21st Nov 2024
$37.50 → $30.00
20% drop
Price Drop 9th Oct 2024
$37.50 → $35.25
6% drop
Price Drop 3rd Sep 2024
$37.50 → $35.25
6% drop
Price Drop 17th Jul 2024
$37.50 → $33.75
10% drop
Price Drop 3rd Jun 2024
$37.50 → $33.75
10% drop
Price Drop 28th Apr 2024
$37.50 → $26.25
30% drop
Price Drop 2nd Jun 2022
$39.98 → $37.50
6.2% drop
Product Information
Details
| Product Name | 3 Pair Polarized Replacement Lenses for Oakley Gascan OO9014 Pack |
|---|---|
| Store Product Code | B07F7312CT |
| Store Name | amazon.com |
| Rating | 8.4 / 10 |
| Category | Replacement Sunglass Lenses |
Images
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Rating and Reviews
8.4 Based on 118 reviews
3 Pair Polarized Replacement Lenses for Oakley has 8.4 rating out of 10. This average rating is consist of 118 individual ratings. You can rate this product at product review page.
* Predictions is created on based of past prices and trends, it does not guarantee that it will happen. These are just prediction for theoretical information only.