20th Jul 2026, 10:09 AM
1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook OO9102 /Holbrook XL OO9417 /Holbrook Metal OO4123 Sunglasses
Price may vary by location, shipping cost, and availability.
$24.59
+ $1
Highest: $25.59
Average: $22.77
Lowest: $12.30
Price History Graph
Offer Price Prices
Lowest: -
Average: -
Highest: -
Price History Information
You can check the price history of 1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook OO9102 /Holbrook XL OO9417 /Holbrook Metal OO4123 Sunglasses here. This product's current Price in USA is $24.59. The average and highest prices are $22.77 and $25.59 respectively. The current offer price of the product is $25.59.
| Lowest Ever Price | $12.30 |
|---|---|
| 2nd Dec 2025 | |
| Average Price | $22.77 |
| Based on 1061 days price tracking | |
| Highest Price | $25.59 |
| 23rd Feb 2026 | |
Price History of All Variants of 1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook...
Current Price in USA
| Price | $24.59 |
|---|
Recent Price Drops on 1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook OO9102 /Holbrook XL OO9417 /Holbrook Metal OO4123 Sunglasses
Price Drop 6th Jan 2026
$24.59 → $12.30
49.98% drop
Price Drop 1st Dec 2025
$24.59 → $12.30
49.98% drop
Price Drop 3rd Jul 2025
$24.59 → $19.67
20.01% drop
Price Drop 3rd Oct 2024
$24.59 → $18.44
25.01% drop
Product Information
Details
| Product Name | 1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook OO9102 /Holbrook XL OO9417 /Holbrook Metal OO4123 Sunglasses |
|---|---|
| Store Product Code | B0C5ZBC5D3 |
| Store Name | amazon.com |
| Rating | 8.6 / 10 |
| Category | Replacement Sunglass Lenses |
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Rating and Reviews
8.6 Based on 36 reviews
1.8MM Polycarbonate Replacement Lenses for Oakley Holbrook has 8.6 rating out of 10. This average rating is consist of 36 individual ratings. You can rate this product at product review page.
* Predictions is created on based of past prices and trends, it does not guarantee that it will happen. These are just prediction for theoretical information only.